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doors open every 20 secs, so it opens at least 6 times during the 2 minutes a round lasts in LMS.

there are 8 rooms.

let's tell there are 2 players only, because even if there are 4, 5 or 6 it still finishes by a final duel.

**well:**

**how much odds have they to meet each other at the beginning ?** there are 3 respawns points a room it means there are 24 respawns. then, when we start a door is already oppenned, it's like if there were only 4 rooms. on the 24 respawns, on is already used by the first who spawns, so there are more odds to spawn somewhere else than to spawn in the "big room" (composed of 2 rooms) where the first player is.

there are so 5 usable spawns here against 6 anywhere else.

they have so 5/23 odds to meet the ennemy when we start, and so 18/23 odds to respawn somewhere else.

**they don't meet at the beginning, and they join the room delivered by doors, how much odds have they to meet each other ?**if they don't meet at the beginning, there are only 2 senses so there are only 2 possibilities, they run in the same sense, and they never meet at each other, or they run in a diferent sense and they meet at each other. 1/2 odds so

**how much odds have they to meet each other if they join the room delivered by doors every 20s?**1/2 + 5/23 = 23/46 + 10/46 = 33/46

**now, one decides to stay in the room of the begginning whereas the other still joins other rooms... how much odds they have to meet each other?**[/b]

1 / 2 --> 3 --> 4 --> 5 --> 6 --> 7 --> 8 --> 1...

So, let's imagine the first players (who moves) is on the "room 1" and the other (who stays in his room) is on the the "room 5", there are 2 senses so 2 possible scenarios.

he can naturally join the room 8 from the room 1.

in the room where we start, one set of door is already openned, so he can join directly the room 2, he hasn't to wait 20s to open like he'd do to join the room 8.

First: 2 --> 3 --> 4 --> 5, he does 3 displacements where he waits the doors' oppening 20s, this way lasts 1 minute !

Second: 1 --> 8 --> 7 --> 6 --> 5, he does 4 displacements, this way lasts 1 minute and 20s

in any case he joins the other. 1/1 !!!

But ! if the ennemy was in

and if he decided to take the first way (1-->2 -->3..) he would get there on 6 displacements (so 2 minutes), what happens at the end of the count happens, he meets the ennemy but he loses his health in the same time. (but he joins it.. anyway..)

**the 2 players decide to stay on their room, how much odds have they to meet at each other?**After some long and boring calculation I got at the conclusion that they would never meet at each other if they wouldn't start in the same room, it means 5/23 odds to...

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So, in the case of a 2v2, or a final duel where players wouldn't change their way to move. there would be 3 diferent possibilities:

**they joins rooms when doors open:** 33/46

**only one moves, the other waits**: 1/1 (yup !!)

**no one moves:** 5/23

it happens rarely so, that they never meet each other.

ps: it's a bit paradoxal, because the best way to play this map is so, doing anything, but if the 2 players don't do anything they have almost no odds to finish it... if we want to finish it we must know so how the ennemy will move... it's all an art